In: Statistics and Probability
How much time do you spend talking on your phone per day? I would like you to guess the number of minutes. This is your null hypothesis. I then want you to secure the data from your phone for the past month and conduct a one sample hypothesis test of the mean length of your phone calls per day. Be sure to show all your work by using excel and include your data set. Use a significance level of 0.05. You will have approximately 30 data values showing the total of minutes you spend per day. (Look at last month’s total and divide by the number of days.) Your phone bill will provide this information.
Let my talking time is 30 minutes in a day. so this is our null hypothesis. Now let us check the phone record of 30 days. I got the following values in minutes and entered in excel and use to to perform t test of mean, whose statistics is given by
Tiime | Total time | (Time-mean(time))^2 | |
1 | 22 | 22 | 104.7211 |
2 | 28 | 50 | 17.92111 |
3 | 22 | 72 | 104.7211 |
4 | 17 | 89 | 232.0544 |
5 | 18 | 107 | 202.5878 |
6 | 49 | 156 | 281.1211 |
7 | 42 | 198 | 95.38778 |
8 | 32 | 230 | 0.054444 |
9 | 28 | 258 | 17.92111 |
10 | 47 | 305 | 218.0544 |
11 | 40 | 345 | 60.32111 |
12 | 45 | 390 | 162.9878 |
13 | 41 | 431 | 76.85444 |
14 | 35 | 466 | 7.654444 |
15 | 30 | 496 | 4.987778 |
16 | 25 | 521 | 52.32111 |
17 | 38 | 559 | 33.25444 |
18 | 41 | 600 | 76.85444 |
19 | 26 | 626 | 38.85444 |
20 | 26 | 652 | 38.85444 |
21 | 18 | 670 | 202.5878 |
22 | 23 | 693 | 85.25444 |
23 | 33 | 726 | 0.587778 |
24 | 34 | 760 | 3.121111 |
25 | 47 | 807 | 218.0544 |
26 | 36 | 843 | 14.18778 |
27 | 31 | 874 | 1.521111 |
28 | 33 | 907 | 0.587778 |
29 | 21 | 928 | 126.1878 |
30 | 39 | 967 | 45.78778 |
Total | 967 | 2525.367 | |
Mean | 32.23333 | 87.08161 | |
t= | 0.243418 |
As at 5% level of significance critical value of t at 29 df is 2.05 and as our t value is 0.243418 which is less that critical value so we can not reject our null hypothesis.