Solve the recurrence equations by Substitution a) T(n) = 4T (n/2) + n, T (1) =...

Solve the recurrence equations by Substitution

a) T(n) = 4T (n/2) + n, T (1) = 1

b) T(n) = 4T (n/2) + n² , T (1) = 1

c) T(n) = 4T (n/2) + n³ , T (1) = 1

Expert Solution

Colby Messinger answered 2 years ago

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6. Solve the following recurrence relations t(n) = t(n-1) + 3 for n>1 t(1) = 0...

6. Solve the following recurrence relations t(n) = t(n-1) + 3 for n>1 t(1) = 0 t(n) = t(n-1) + n for n>1 t(1) = 1 t(n) = 3t(n/2) + n for n>1, n is a power of 2 t(1) = ½ t(n) = 6t(n-1) – 9t(n-2) for n>1 t(0) = 0 t(1) = 1

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Solve the following recurrence relations. a. x(n) = x(n − 1) + 3 for n >...

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