6. Solve the following recurrence relations
t(n) = t(n-1) + 3 for n>1
t(1) = 0
t(n) = t(n-1) + n for n>1
t(1) = 1
t(n) = 3t(n/2) + n for n>1, n is a power
of 2
t(1) = ½
t(n) = 6t(n-1) – 9t(n-2) for n>1
t(0) = 0 t(1) = 1
Solve the recurrence equations by Substitution
a) T(n) = 4T (n/2) + n, T (1) = 1
b) T(n) = 4T (n/2) + n2 , T (1) = 1
c) T(n) = 4T (n/2) + n3 , T (1) = 1
1. Using domain and range transformations, solve the following
recurrence relations:
a) T(1) = 1, T(n) = 2T(n/2) + 6n - 1
b) T(1) = 1, T(n) = 3T(n/2) + n^2 - n
Find and solve a recurrence relation for the number of ways to stack n poker
chips using red, white and blue chips such that no two red chips are together.
Use your solution to compute the number of ways to stack 15 poker chips.
Solve the following recurrence relations. a. x(n) = x(n − 1) + 3
for n > 1, x(1) = 0 b. x(n) = 5x(n − 1) for n > 1, x(1) = 6
c. x(n) = x(n/5) + 1 for n > 1, x(1) = 1 (solve for n = 5k )