solve the initial values: if Y(3)-4Y"+20Y'=51e^3x Y"(0)=41, Y'(0)= 11. Y(0)= 7 > solution is Y(x)= e^3x+2...

solve the initial values:

if Y(3)-4Y"+20Y'=51e^3x

Y"(0)=41, Y'(0)= 11. Y(0)= 7 > solution is Y(x)= e^3x+2 e^2x sin(4x)+6

so, what is the solution for:

Y(3)-8Y"+17Y'=12e^3x

Y"(0)=26, Y'(0)= 7. Y(0)= 6

Y(x)=???

Expert Solution

Colby Messinger answered 6 months ago

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Question

solve the initial values: if Y(3)-4Y"+20Y'=51e^3x Y"(0)=41, Y'(0)= 11. Y(0)= 7 > solution is Y(x)= e^3x+2...

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