find the general solution 2xy^3+e^x+(3x^2y^2+siny)y'=0 xy'=6y+12x^4y^(2/3) (2x+1)y'+y=(2x+1)^(3/2)

find the general solution

2xy^3+e^x+(3x^2y^2+siny)y'=0

xy'=6y+12x^4y^(2/3)

(2x+1)y'+y=(2x+1)^(3/2)

Expert Solution

Colby Messinger answered 1 year ago

Find the general solution of the ODE: y'' − 6y' + 9y = (1 + x^2)e^2x...

Find the general solution of the ODE: y'' − 6y' + 9y = (1 + x^2)e^2x .

Find the general power series solution for the differential equation 2x^2y''-xy'+(x^2 +1) y =0 about x=0...

Find the general power series solution for the differential equation 2x^2y''-xy'+(x^2 +1) y =0 about x=0 (Answer should be given to the x^4+r term)

Find the general solution of the following equations: y′′ −4y′ +4y=0; y′′ −5y′ +6y=0; y′′ −...

Find the general solution of the following equations: y′′ −4y′ +4y=0; y′′ −5y′ +6y=0; y′′ − 2y′ = 0

Let Q1=y(2) Q2 =y(3) where y=y(x) solves y'+2xy=2x^3 y(0)=1 dy/dx= (2x-y)/(x+4y) y(1)=1 y'+ycotx=y^3sin^3x y(pi/2)=1 (y^2-2x)dx+2xy dy=0 ...

Let Q1=y(2) Q2 =y(3) where y=y(x) solves y'+2xy=2x^3 y(0)=1 dy/dx= (2x-y)/(x+4y) y(1)=1 y'+ycotx=y^3sin^3x y(pi/2)=1 (y^2-2x)dx+2xy dy=0 y(1)=1 2x^2y;+4xy=3sinx y(2pi)=0 y"+2y^-1 (y')^2=y'

Question : y''=4y'+8y=0 , (y''-4y'+13y)^2=0 , (y''+2y'+2y)^2=0 , y''-6y'+13y=0,y(0)=3 , y'(0)=13 , 2y''-6y'+17y=0,y(0)=2, y'(0)=13

Find the solution of the equation given around x_0 = 0. (1+x^2)y"+2xy'-2y=0

Undetermined Coefficients: a) y'' + y' - 2y = x^2 b) y'' + 4y = e^3x

Undetermined Coefficients: a) y'' + y' - 2y = x^2 b) y'' + 4y = e^3x c) y'' + y' - 2y = sin x d) y" - 4y = xe^x + cos 2x e) Determine the correct form of a particular solution, do not solve y" + y = sin x

Maximize z=x+4y Subject to 2x+6y<= 36 4x+2y<= 32 x>= 0 y>= 0 Maximum is ___________ at...

Maximize z=x+4y Subject to 2x+6y<= 36 4x+2y<= 32 x>= 0 y>= 0 Maximum is ___________ at x = ______ y = ______

a.) Show that the DE is exact and find a general solution 2y - y^2sec^2(xy^2)+[2x-2xysec^2(xy^2)]y' =...

a.) Show that the DE is exact and find a general solution 2y - y^2sec^2(xy^2)+[2x-2xysec^2(xy^2)]y' = 0 b.) Verify that the equation is not exact. Multiply by integrating factor u(x, y) = x and show that resulting equation is exact, then find a general solution. (3xy+y^2) + (x^2 + xy)dy/dx = 0 c.) Verify that the equation is not exact. Multiply by integrating factor u(x, y) = xy and show that resulting equation is exact, then find a general solution....

find the general solution y'''-y''-4y'+4y=5-e^x-4e^2x (UNDETERMINED COEFFICIENTS—SUPERPOSITION APPROACH)

Question