Billiard ball A of mass mA = 0.116 kg moving with speed vA = 2.80 m/s...

Billiard ball A of mass mA = 0.116 kg moving with speed vA = 2.80 m/s strikes ball B, initially at rest, of mass mB = 0.135 kg . As a result of the collision, ball A is deflected off at an angle of θ′A = 30.0∘ with a speed v′A = 2.10 m/s, and ball B moves with a speed v′B at an angle of θ′B to original direction of motion of ball A. Solve these equations for the speed, v′B, of ball B after the collision. Do not assume the collision is elastic.

Expert Solution

genius_generous answered 7 months ago

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