a) Fill out the following table with the values in R0 and R1 after each instruction...

a) Fill out the following table with the values in R0 and R1 after each instruction is executed. Please use hexadecimal. The first line is completed for you. (4 pts)

Address	Instruction	R0	R1
0100₁₆	1110 0001 1111 1100	00FD₁₆	0000₁₆
0101₁₆	0001 0010 0011 1101
0102₁₆	0011 0011 1111 0100
0103₁₆	0101 0010 0110 0000
0104₁₆	0010 0001 1111 0110

b) Explain what the instruction at each of the following addresses does. (4 pts)

Address 0101₁₆:
Address 0102₁₆:
Address 0103₁₆:
Address 0104₁₆:

c) What is the value stored in PC when the instruction at address 0102₁₆ is executed? (1 pt)

Expert Solution

Answer a

Address	Instruction	R0	R1
0100₁₆	1110 0001 1111 1100	00FD₁₆	0000₁₆
0101₁₆	0001 0010 0011 1101	00FD₁₆	00FA₁₆
0102₁₆	0011 0011 1111 0100	00FD₁₆	00FA₁₆
0103₁₆	0101 0010 0110 0000	00FD₁₆	00FA₁₆
0104₁₆	0010 0001 1111 0110	Mem[00FB‬₁₆]	00FA₁₆

Answer b

Address	Instruction	Description
0100₁₆	1110 0001 1111 1100	PC = 0101₁₆ LEA R0, FD 1110 - LEA (Load Effective Address) 000 - R0 1 1111 1100 - PC Offset R0 = PC + Sign Extended Offset = = 0000 0001 0000 0001 + 1111 1111 1111 1100 = 0000 0000 1111 1101 = 00FD₁₆
0101₁₆	0001 0010 0011 1101	PC = 0102₁₆ 0001 - ADD 001 - R1 000 - R0 1 1101 - Immed5 R1 = R0 + sign extended Immed5 = 0000 0000 1111 1101 + 1111 1111 1111 1101 = 0000 0000 1111 1010‬ = 00FA₁₆
0102₁₆	0011 0011 1111 0100	PC = 0103₁₆ 0011 - ST (Store) 001 - R1 1 1111 0100 - PC Offset [PC + Sign extended PC offset] = R1 [0000 0001 0000 0011 + 1111 1111 1111 0100] = 00FA₁₆ [00F7₁₆] =00FA₁₆
0103₁₆	0101 0010 0110 0000	PC = 0104₁₆ 0101 - AND 001 - R1 001 - R1 0 0000 - Immed5 R1= R1 AND Sign Exteneded Immed 5 = 00FA₁₆ + 0000₁₆ = 00FA₁₆
0104₁₆	0010 0001 1111 0110	PC = 0105₁₆ 0010 - LD (Load) 000 - R0 1 1111 0110 - PC Offset R0 = Mem[PC + Sign Extended PC Offset] = Mem[0105₁₆ + FFF6₁₆] = Mem[00FB‬₁₆]

Answer c

PC = 0103₁₆

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