A ball, mass m1 = 0.1 kg, is moving upwards with a speed of 10 m/s...

A ball, mass m1 = 0.1 kg, is moving upwards with a speed of 10 m/s when it collides inelastically with a cup, mass m2 = 0.9 kg, that is initially at rest. After the collision the system (ball+cup) moves straight upwards without rotating. This collision occurs on Earth, and the local gravitational field points down with g = 9.8 m/s2 .

(a) What is the momentum of the system before the collision? Write your final answers and neatly show your work on the answer page

(b) What is the momentum of the system after the collision? Write your final answers and neatly show your work on the answer page

(c) The kinetic energy is not conserved in the inelastic collision. What happens to it? Write your final answers and neatly show your work on the answer page

(d) What is the kinetic energy of the system (ball+cup) after the collision? Write your final answers and neatly show your work on the answer page

(e) To what final height will the system (ball+cup) rise after the collision?

Please show equations to be used with all variables, draw free body diagrams if applicable, all steps to the solution (so that if i were to have a similar problem I could solve), and please use 9.8 for gravity. I will rate quickly, thank you.

Expert Solution

genius_generous answered 2 years ago

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