In: Chemistry
The equilibrium constant in terms of pressures for the reduction of
tungsten(IV) oxide to tungsten at
25 °C is Kp = 3.82×10-4,
corresponding to the reaction
If the total pressure of an equilibrium system at 25 °C is
2.67 atm, calculate the partial pressures of
CO(g) and
CO2(g).
PCO = atm
PCO2 = atm
Few things we have to remember in this type of problems. The total pressure given in the problem is the sum of the partial pressure of the gas components. So here also the sum of the partial pressure of CO2 and CO is the total pressure. Another thing is that the partial pressure applying by solid components is measured as 1. So, we can reduce the equilibrium constant in terms of pressure (Kp) by eliminating these terms. The partial pressure of both the gases are calculated here. We can do a back calculation also to check the answer if it is right or wrong.