In: Chemistry
Use cell potential to calculate an equilibrium constant.
Calculate the cell potential and the equilibrium constant for the following reaction at 298 K:
Cu2+(aq) + Hg(l) = Cu(s) + Hg2+(aq)
Hint: Carry at least 5 significant figures during intermediate
calculations to avoid round off error when taking the
antilogarithm.
Equilibrium constant: -------
Hg(l) ---------------> Hg^2+(aq) + 2e^- E0 = -0.85v
Cu^2+ (aq) + 2e^- ----------> Cu(s) E0 = 0.34v
-----------------------------------------------------------------------------
Cu2+(aq) + Hg(l) ---------> Cu(s) + Hg2+(aq) E0 cell = -0.51v
n = 2
G0 = -nEcell*F
= -2*-0.51*96500
= 98430J
G0 = -RTlnK
98430 = -8.314*298*2.303logK
logK = -98430/5705.8483
logK = -17.25
K = 10^-17.25 = 5.6234*10^-18 >>>>>>answer