Question

php please

// 5) isArraySorted

// Given an array , return true if the element are in ascending order.

// Note: 'abe' < 'ben' and 5 > 3

// Precondition $arr has all the same type of elements

function isArraySorted($arr) {

  

}

echo PHP_EOL . 'isArraySorted(array(1, 2, 2, 99) 1: ' . isArraySorted ( array (

1,

2,

2,

99 ) ) . "\n";

assert ( isArraySorted ( array (

1,

2,

2,

99 ) ) );

echo 'isArraySorted(array(2, 2, 1) false: ' . isArraySorted ( array (

2,

2,

1 ) ) . "\n";

Answer 1

The solution for the above problem is given below with the screenshots for indentation and if you feel any problem then feel free to ask.

<?php

// defining a function isArraySorted and passing an array into it as argument

function isArraySorted($arr)

{

// storing the size of array in separate variable

$n = sizeof($arr);

// returning true if the size of array is 1 or 0

if($n<2)

{

return "true";

}

else {

// loop for returning if any greater value is occured before smaller value relative to it

for ($i=0; $i < $n-1 ; $i++) {

if ($arr[$i] > $arr[$i+1])

{

return "false";

}

}

//returning true if no greater value occured before smaller one

// implying the array is in ascending order

return "true";

}

}

echo PHP_EOL . 'isArraySorted(array(1, 2, 2, 99) 1: ' . isArraySorted ( array (1,2,2,99 ) ) . "\n";

assert ( isArraySorted ( array (1,2,2,99 ) ) );

echo 'isArraySorted(array(2, 2, 1) false: ' . isArraySorted ( array (2,2,1 ) ) ."\n";

?>

NOTE:- If you want to print true or false then this is for that as it is returning true/false as strings but if you want to get the boolean values then you can change the return statement simply from "true"/"false" to true/false. But in the case of bool the echo command do not produce output for false and for true it generates 1.