Question

Trace the following code segment

1. use the red numbers under each statement to show the order that you execute the code by.

For example: (1) means int p=3; (2) means p<10; (3) means p+=3;

(1)(2)(3) means you execute int p=3 then p<10 then P+=3;

(2)(1)(3) means you execute p<10 then int p =3 then P+=3;

2. show its output:

int x = 30,  num = 100;

    (1)   

while ( x > 0)

(2)

          {

cout   <<   endl

                         <<  “ x =“   <<   x    <<   “ “   <<   “num =”   <<   num;

  (3)

              x   - = 10;

  (4)

num += x;

(5)

}

Answer 1

Initially we have given value to x and num which means that the red number intially is 1

Then the while loop condition is checked which means the red number is 2 and after we enter inside the loop , the value of x is printed thus red number here is 3 and xchanges to 20 and num changes to 120 which means that the red number here is 4 and 5 respectively

The red number order for iteration 1 is (1)(2)(3)(4)(5)

For iteration 2 :

First the condition is checked and thus red number is 2 then the value of x gets printed which means the red number here is 3 and we change the values of x to 10 and num to 130 which means the red number here is (4)then (5) again since both the values are changed .

The red number for iteration 2 is (2)(3)(4)(5)

Iteration 3:

First we check the condition of while loop thus red number is (2) and then x is printed which means red number is 3 and the value of x becomes 0 and num remains 130

Which means the red number order for iteration 3 is (2)(3)(4)(5)

Further the loop will not run since x=0, but we check the condition here, thus (2) gets executed and after this the program ends.

Hope this resolves your doubt.

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