Question

1. Show the output of the following code segment.

int count=0;

                        for (int i=2; i <= 4; i++ ) {

                                    StdOut.println(i);

                                    for (int j=1; j <3; j++) {

                                                count++;

                                                StdOut.println(i +" " + j +" "+ count);

                                    }

                        }

count	i	j	I print
0	2	1	3	1	1
1		2	3	2	2
		3	3	3	3
		4
			3

2. Show the output of the function call statements shown.

1.             double x = funk2( -2 , 5.0, 7) );

StdOut.println( “ call 1” + x );

2.             StdOut.println( “ call 2” + funk2(­ 1, 2.0, 4 );

public static double funk2( int a, double b, int c) {

                        int x = 15;

                        double result;

                        result = b - a*c;

                        if ( result <= x)

                                    StdOut.println( " result " + b);

                        else

                                    StdOut.println(" comp " + result);

                        return result;

            }

Answer 1

Please find the answer for the above given questions..

a )

OUTPUT :

CODE :

class Main {

public static double funk2( int a, double b, int c) {

int x = 15;

double result;

result = b - a*c;

if ( result <= x)

System.out.println( "result " + b);

else

System.out.println("comp " + result);

return result;

}

public static void main(String[] args) {

double x = funk2( -2 , 5.0, 7);

System.out.println("call 1 : " + x );

}

}

b )

OUTPUT :

CODE :

class Main {

public static double funk2( int a, double b, int c) {

int x = 15;

double result;

result = b - a*c;

if ( result <= x)

System.out.println( "result " + b);

else

System.out.println("comp " + result);

return result;

}

public static void main(String[] args) {

double x = funk2( 1, 2.0, 4);

System.out.println("call 2 : " + x );

}

}

Thanks..