A 27.5 L sample of oxygen gas is at 25°C and 1.05 atm. If the gas...

A 27.5 L sample of oxygen gas is at 25°C and 1.05 atm. If the gas is cooled to –

40.°C while the pressure is increased to 2.00 atm, calculate the new volume of the

gas.

Can u please show with dymentional analysis?

Solutions

Expert Solution

Initial conditions:

Pressure P1 = 1.05 atm

Volume V1 = 27.5 L

Temperature T1 = 25 ^oC = 25 + 273 K = 298 K

Final conditions:

Pressure P2 = 2 atm

Volume V2 = ? L

Temperature T2 = -40 ^oC = -40+ 273 K = 233 K

We knaow that P1V1/T1 = P2V2/T2

V2 = (P1V1/T1) (T2/P2)

= ( 1.05 atm x 27.5 L/ 298 K ) ( 233 K/ 2 atm)

= 11.28 L

V2 = 11.28 L

Therefore,

new volume of the gas = 11.28 L

queen_honey_blossom answered 4 months ago

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