Titrate 40.0 mL of 0.0350 M benzoic acid (C6H5COOH, Ka = 6.3 ×
10–5) with 0.0700...
Titrate 40.0 mL of 0.0350 M benzoic acid (C6H5COOH, Ka = 6.3 ×
10–5) with 0.0700 M NaOH Calculate the pH in the solution after
addition of 25.0 mL of 0.0700 M NaOH.
a) 2.269
b) 8.284
c) 9.845
d) 11.731
e) 5.628
25.0 mL of a 0.500 M solution of benzoic acid
(C6H5COOH, Ka = 6.5 ×
10-5) is treated with 25.0 mL of a 0.400 M solution of
KOH. Determine the pH of the solution.
A.
4.79
B.
4.29
C.
4.09
D.
3.59
94. A 50.00-mL solution of 0.0350 M benzoic acid (Ka = 6.4 ×
10-5) is titrated with a 0.0209 M solution of sodium hydroxide as
the titrant. What is the pH of the acid solution after 15.00 mL of
titrant have been added? (Kw = 1.00 × 10-14) a. 1.46 b. 2.83 c.
3.56 d. 10.13 e. 4.19
ANSWER: c
You titrate 50.0 mL of 0.100 M benzoic acid (C6H5COOH) with
0.250 M KOH. What is the pH of the final solution at the
equivalence point? Ka of C6H5COOH = 6.3 x 10-5.
If all work could be shown I would appreciate it! I'm super
confused.
The acid-dissociation constant for benzoic acid (C6H5COOH) is
6.3×10−5.
A. Calculate the equilibrium concentration of H3O+ in the
solution if the initial concentration of C6H5COOH is
5.1×10−2M
B. Calculate the equilibrium concentration of C6H5COO− in the
solution if the initial concentration of C6H5COOH is
5.1×10−2 M .
C. Calculate the equilibrium concentration of C6H5COOH in the
solution if the initial concentration of C6H5COOH is
5.1×10−2 M .
If 10 mL of 0.025 M benzoic acid (Ka = 6.5 *
10-5) is titrated with 0.01 M NaOH, what is pH after 0
ml, 20 ml, 50 ml, and 90 ml of base have been added?
Find the pH during the titration of 20.00 mL of 0.1460 M benzoic
acid, C6H5COOH (Ka = 6.3 ✕ 10-5), with 0.1460 M NaOH solution after
the following additions of titrant.
A) 0 mL
B) 10.00 mL
C) 15.00 mL
D) 19.00 mL
Find the pH during the titration of 20.00 mL of 0.2850
M benzoic acid, C6H5COOH
(Ka = 6.3 10-5), with
0.2850 M NaOH solution after the following additions of
titrant.
(a) 0 mL
(b) 10.00 mL
(c) 15.00 mL
(d) 20.00 mL
(e) 25.00 mL
Find the pH during the titration of 20.00 mL of
0.2290 M benzoic acid, C6H5COOH
(Ka = 6.3 ✕ 10-5), with 0.2290
M NaOH solution after the following additions of
titrant.
(a) 0 mL =
(b) 10.00 mL =
(c) 15.00 mL =
(d) 19.00 mL =
(e) 19.95 mL =
(f) 20.00 mL =
(g) 20.05 mL =
(h) 25.00 mL =
Please help..!!!
xoxo
Find the pH during the titration of 20.00 mL of 0.2830
M benzoic acid, C6H5COOH
(Ka = 6.3 ✕ 10-5), with 0.2830
M NaOH solution after the following additions of
titrant.
(a) 0 mL
(b) 10.00 mL
(c) 15.00 mL
(d) 19.00 mL
(e) 19.95 mL
(f) 20.00 mL
(g) 20.05 mL
(h) 25.00 mL