Question

In: Chemistry

25.0 mL of a 0.500 M solution of benzoic acid (C6H5COOH, Ka = 6.5 × 10-5)...

25.0 mL of a 0.500 M solution of benzoic acid (C6H5COOH, Ka = 6.5 × 10-5) is treated with 25.0 mL of a 0.400 M solution of KOH. Determine the pH of the solution.

A.

4.79   
B.

4.29   
C.

4.09      
D.

3.59

Solutions

Expert Solution

queen_honey_blossom answered 2 years ago
Next > < Previous

Related Solutions

If 10 mL of 0.025 M benzoic acid (Ka = 6.5 * 10-5) is titrated with...
If 10 mL of 0.025 M benzoic acid (Ka = 6.5 * 10-5) is titrated with 0.01 M NaOH, what is pH after 0 ml, 20 ml, 50 ml, and 90 ml of base have been added?
Titrate 40.0 mL of 0.0350 M benzoic acid (C6H5COOH, Ka = 6.3 × 10–5) with 0.0700...
Titrate 40.0 mL of 0.0350 M benzoic acid (C6H5COOH, Ka = 6.3 × 10–5) with 0.0700 M NaOH Calculate the pH in the solution after addition of 25.0 mL of 0.0700 M NaOH. a) 2.269 b) 8.284 c) 9.845 d) 11.731 e) 5.628
Determine the pH of a 0.150 M benzoic acid solution with a  Ka = 6.5 x 10–5.  ...
Determine the pH of a 0.150 M benzoic acid solution with a  Ka = 6.5 x 10–5.   - report the answer in three significant figures
Calculate the pH when 15.0 mL of 0.20 M benzoic acid (HC7H5O2, Ka = 6.5 ×10–5)...
Calculate the pH when 15.0 mL of 0.20 M benzoic acid (HC7H5O2, Ka = 6.5 ×10–5) is titrated with 20.0 mL of 0.15 M sodium hydroxide (NaOH). A. 8.56 B. 7.95 C. 5.33 D. 6.25
Calculate the pH when 15.0 mL of 0.20 M benzoic acid (HC7H5O2, Ka = 6.5 ×10–5)...
Calculate the pH when 15.0 mL of 0.20 M benzoic acid (HC7H5O2, Ka = 6.5 ×10–5) is titrated with 20.0 mL of 0.15 M sodium hydroxide (NaOH).
A) A chemist titrates a 25.0 mL sample of 0.191 M benzoic acid (C6H5COOH) against a...
A) A chemist titrates a 25.0 mL sample of 0.191 M benzoic acid (C6H5COOH) against a 0.100 M solution of NaOH. The overall reaction is shown by the equation below: $$C6​H5​COOH(aq)+NaOH(aq) C6​H5​COONa(aq)+H2​O(l) The Ka value for benzoic acid is 6.28 × 10–5. Calculate the pH at the start of the titration, before any NaOH has been added. Give your answer correctly to two places after the decimal. B) What will the pH be when 12.0 mL of 0.100 M NaOH...
Calculate the percent dissociation of 0.40 M benzoic acid, C6H5COOH. (Ka = 6.3 x 10^-5) ___%?
Calculate the percent dissociation of 0.40 M benzoic acid, C6H5COOH. (Ka = 6.3 x 10^-5) ___%?
94. A 50.00-mL solution of 0.0350 M benzoic acid (Ka = 6.4 × 10-5) is titrated...
94. A 50.00-mL solution of 0.0350 M benzoic acid (Ka = 6.4 × 10-5) is titrated with a 0.0209 M solution of sodium hydroxide as the titrant. What is the pH of the acid solution after 15.00 mL of titrant have been added? (Kw = 1.00 × 10-14) a. 1.46 b. 2.83 c. 3.56 d. 10.13 e. 4.19 ANSWER: c
The Ka of benzoic acid is 6.5 x 10 ^(-5) a) Calculate the pH of a...
The Ka of benzoic acid is 6.5 x 10 ^(-5) a) Calculate the pH of a 40.00 mL, 0.1 M benzoic acid buffer solution after the addition of 20.00 mL of a 0.1M NaOH b) Calculate the pH of a 40.00 mL, 0.1 M benzoic acid buffer solution after the addition of 50.00 mL of a 0.1M NaOH REDOX TITRATION 2) Express the reactions for potassium permanganate titration with sodium oxalate: Hint: include the 2 half-reactions. 3) What is the...
Calculate the pH for 300. mL of a 0.850 M solution of the benzoic acid, (C6H5COOH),...
Calculate the pH for 300. mL of a 0.850 M solution of the benzoic acid, (C6H5COOH), Ka=6.30x10-5 ) being titrated with 0.850 M NaOH at the following positions in the titration. a) The initial pH (before any NaOH has been added). a. 1.436 b. 12.864 c. 5.435 d. 8.534 e. 2.136 b) The pH of the solution after 125.0 mL of 0.850 M NaOH has been added. a. 10.034 b. 4.054 c. 3.543 d. 8.534 e. 2.132 c) The pH...
ADVERTISEMENT
Subjects
ADVERTISEMENT
Latest Questions
ADVERTISEMENT