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25.0 mL of a 0.500 M solution of benzoic acid (C6H5COOH, Ka = 6.5 × 10-5)...

25.0 mL of a 0.500 M solution of benzoic acid (C6H5COOH, Ka = 6.5 × 10-5) is treated with 25.0 mL of a 0.400 M solution of KOH. Determine the pH of the solution.

A.

4.79   
B.

4.29   
C.

4.09      
D.

3.59

Solutions

Expert Solution

queen_honey_blossom answered 2 years ago
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