Question

1. How many grams O₂
   are needed to react completely with 2.60 mole FeS, in this reaction?      
   4 FeS + 7 O₂→2 FeO₃ + 4 SO₂

   		1.28 x 10 3 g
   		0.258 g
   		329 g
   		44.1 g
   		3.90 x 10 3 g
   		146 g
   		74.7 g
   		1.81 g

2. How many g of Aluminum are needed to react completely with 12.5 mole of Br₂, according to the chemical equation below?
   2Al + 3Br₂→Al₂Br₆
   

   		36.6 g
   		310 g
   		225 g
   		1.42 g
   		145 g

3. How many g of Aluminum are needed to react completely with 0.850 gram of Mn₃O₄, according to the chemical equation below?
   3 Mn₃O₄   + 8 Al --> 9 Mn    +    4 Al₂O₃

   		0.267 g
   		79.2 g
   		20.3 g
   		151 g
   		13.3 g
   		86.5 g
   		14.2 g
   		3.70 g

4. Refer to this equation:
   3SCl₂(l) + 4NaF(s) → SF₄(g) + S₂Cl₂(l) + 4NaCl(s)
   12.0 grams SCl₂ is reacted and 3.05 grams of SF₄ is formed. What is percent yield SF₄?
     
   Hint: find theoretical yield
   Hint: percent yield =(actual yield/ theoretical yield) x 100

   		19.3 %
   		64.4%
   		38.0%
   		27.2 %
   		82.1%
   		72.7%
   		90.1%
   		58.6%

5. Look at the following equation:   
      3H ₂ +   N ₂ ->   2 NH ₃
   
   If 85.0 gram of N ₂ gives 86.2 g of NH ₃, what is the percent yield of
   NH ₃?
   Hint: find theoretical yield
   Hint: percent yield =(actual yield/ theoretical yield) x 100

   		71.7 %
   		69.2 %
   		93.0%
   		45.1%
   		83.5 %
   		36.1%
   		79.2%
   		71.9%

Answer 1

I hope it will help