Question

How many grams of KOH are required to react with 1 mole of H3PO4

3 KOH + HPO4 ----> K3pO4 + 3 H2O

How many grams of glucose (C6H12O6) is produced from 12 moles of CO2 ?

6CO2 + 6 H2O -----> c6H12 O6+ 6 O2

How many grams of carbon dioxide are produced from 10 moles of carbonic acide?

H2CO3 -----> CO2 + H2O

Answer 1

1)

3 KOH + H3PO4 ----> K3pO4 + 3 H2O

from balanced reaction,

mol of KOH required = 3*moles of H3PO4

= 3*1 mole

= 3 mole

Molar mass of KOH,

MM = 1*MM(K) + 1*MM(O) + 1*MM(H)

= 1*39.1 + 1*16.0 + 1*1.008

= 56.108 g/mol

mass of KOH,

m = number of mol * molar mass

= 3 mol * 56.108 g/mol

= 168 g

Answer: 168 g

2)

6CO2 + 6 H2O -----> c6H12 O6+ 6 O2

from balanced reaction above,

mol of glucose = (1/6)*moles of CO2 reacting

= (1/6)*12 moles

= 2 moles

Molar mass of C6H12O6,

MM = 6*MM(C) + 12*MM(H) + 6*MM(O)

= 6*12.01 + 12*1.008 + 6*16.0

= 180.156 g/mol

mass of C6H12O6,

m = number of mol * molar mass

= 2 mol * 180.156 g/mol

= 360 g

Answer: 360 g

3)

H2CO3 -----> CO2 + H2O

from balanced reaction above,

moles of CO2 = moles of H2CO3

= 10 moles

Molar mass of CO2,

MM = 1*MM(C) + 2*MM(O)

= 1*12 + 2*16.0

= 44 g/mol

mass of CO2,

m = number of mol * molar mass

= 10 mol * 44 g/mol

= 440 g

Answer: 440 g