Question

In: Statistics and Probability

Some studies have shown that in the United States, men spend more than women on Valentine's...

Some studies have shown that in the United States, men spend more than women on Valentine's Day. A researcher wants to estimate how much more men spend by observing the amounts spent for random samples of men and women. We want to estimate the difference (µ _men - µ _women) using a 90% confidence interval.

a) Find the AD (Anderson-Darling) for both Men and Women (using Minitab). (round to 3 decimal places)

b) Report the endpoints of the 90% confidence interval below. (Round to 1 decimal place)

Amount(Men)	Amount(Women)
191	10
261	46
173	42
163	48
261	24
62	42
137	48
58	84
205	33
123	34
173	43
236	64

Expert Solution

a)

H0: The data follows normal distribution

H1: The data does not follows normal distribution

Let the los be alpha = 5%

Test Statistic AD = 0.253

P-value = 0.668

Here P-value > alpha 0.05 so we accept H0

thus we conclude that Amount (Men) follows normal distribution

Test Statistic AD = 0.426

P-value = 0.262

Here P-value > alpha 0.05 so we accept H₀

thus we conclude that Amount (Women) follows normal distribution

b) From the given data

orchestra answered 3 years ago

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