Question

In: Biology

Use the data below to answer the questions at the bottom. M: (Vial 0, #47) Red,Wild...

Use the data below to answer the questions at the bottom.

M: (Vial 0, #47) Red,Wild type

F: (Vial 0, #100) Red,Curly

Eye Color   

Wing Shape  

F

M

Total

Red

Curly    

0

79

79

Red

Wild type

81

0

81

Peach

Curly

0

0

0

Peach

Wild type

0

0

0

M: (Vial 0, #1) Peach,Curly

F: (Vial 0, #15) Red,Curly

Eye Color   

Wing Shape  

F

M

Total

Red

Curly    

0

0

0

Red

Wild type

0

0

0

Peach

Curly

156

145

301

Peach

Wild type

0

0

0

M: (Vial 8, #1804) Red,Curly

F: (Vial 0, #5) Peach,Wild type

Eye Color   

Wing Shape  

F

M

Total

Red

Curly    

30

29

59

Red

Wild type

31

33

64

Peach

Curly

32

32

64

Peach

Wild type

28

27

55

M: (Vial 9, #2219) Peach,Curly

F: (Vial 9, #2109) Peach,Curly

Eye Color   

Wing Shape  

F

M

Total

Red

Curly    

34

41

65

Red

Wild type

0

0

0

Peach

Curly

80

80

160

Peach

Wild type

0

0

0

  1. Which traits are dominant? (2pt)

  1. Are these two genes inherited in the same way? Explain your answer. Indicate the mode of inheritance for each gene in your explanation. (2pt)

Solutions

Expert Solution

- Which traits are dominant?

About the curly-wildtype trait, look at the crosses when both parents are curly, they can only produce curly offspring. On the other hand, when the parents are wildtype they are able to produce both curly and wildtype offspring. This means Wildtype is dominant over the recessive curly trait.

In the same manner, addressing the red-peach trait, look at the crosses when both parents are red, they can only produce red offspring, but when both parents are peach they can produce both red and peach offspring. That means Peach is dominant over the recessive red.

- Are these two genes inherited in the same way? Explain your answer. Indicate the mode of inheritance for each gene in your explanation.

For this let's analyze the frequencies but for each trait independently.

+ Wildtype-curly

This treait seems to have a different inheritance mechanism between males and females, as we can see a different result in crossing number one. Let's analyze such crossing with punnet squares for both scenarios (X-linked, and autosomal):

X-linked:

Male: WY

Female: cc

W Y
c Wc cY

If the trait is X linked, then we would obtain half offspring being wildtype female and the other half being curly male.

Autosomal:

Male: Either WW or Wc

Female: cc

W
c Wc

In this case we have both females and males that are only wildtype.

W c
c Wc cc

In this case we have both females and males as either curly or wildtype.

Both autosomal scenarios cannot be seen in reality, while the X-linked scenario fits reality completely. The trait Wildtype-curly is X-linked.

+ Peach-red

This threat shows a regular and expected frequency distribution in the offspring for a regular autosomal trait. Let's make a punnet square with the third crossing to confirm it:

Male: rr

Female: Pr

P r
r Pr rr

We expect half and half (Peach and red), that's just what we found in our real data.

Conclusion: They are not inherited in the same way. The trait Wildtype-curly is X-linked and the trait Peach-red is autosomal.


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