In: Statistics and Probability
Use the Data Below to answer the following question below
0 |
0 |
2 |
0 |
5 |
3 |
1 |
12 |
0 |
0 |
0 |
1 |
6 |
0 |
1 |
1 |
2 |
8 |
1 |
3 |
1 |
6 |
2 |
4 |
0 |
16 |
17 |
0 |
8 |
0 |
3 |
0 |
0 |
1 |
2 |
5 |
2 |
0 |
2 |
1 |
5 |
0 |
7 |
0 |
1 |
0 |
0 |
1 |
0 |
0 |
3 |
1 |
9 |
4 |
1 |
3 |
0 |
1 |
1 |
1 |
0 |
7 |
1 |
9 |
2 |
0 |
1 |
1 |
1 |
1 |
7 |
2 |
7 |
1 |
2 |
===============================
x | f | p(x=x) | P(x<=x) |
0.000 | 22.000 | 0.293 | 0.293 |
1.000 | 21.000 | 0.280 | 0.573 |
2.000 | 9.000 | 0.120 | 0.693 |
3.000 | 5.000 | 0.067 | 0.760 |
4.000 | 2.000 | 0.027 | 0.787 |
5.000 | 3.000 | 0.040 | 0.827 |
6.000 | 2.000 | 0.027 | 0.853 |
7.000 | 4.000 | 0.053 | 0.907 |
8.000 | 2.000 | 0.027 | 0.933 |
9.000 | 2.000 | 0.027 | 0.960 |
12.000 | 1.000 | 0.013 | 0.973 |
16.000 | 1.000 | 0.013 | 0.987 |
17.000 | 1.000 | 0.013 | 1.000 |
75 | 1 |
a) the data is quantitative discrete.
b) quantitative continuous data includes any value between two real value. Since there is no value between 9 and 12, the data is not continuous.
It is definiety not qualitative ordinal data as data is not following a order. therefor the quantitative discrete seems the most viable option.
c) P(x>2) = 1- P(x<=2) = 1- 0.693 = 0.307
P(x<=12) = 0.973
Unusual event is event whose probability is less than 0.05. Since probability of number not more than 12 is 97.3% thus any event occur with number greater than 12 are unusual events as their probabiltity is less than 0.05. Therefore 16 and 17 are ususual events.
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