Show that if Y is a subspace of X, and A is a subset of Y,...
Show that if Y is a subspace of X, and A is a subset of Y, then
the subspace topology on A as a subspace of Y is the same as the
subspace topology on A as a subspace of X.
If X is any topological space, a subset A ⊆ X is compact (in the
subspace topology) if and only if every cover of A by open subsets
of X has a finite subcover.
Suppose x,y ∈ R and assume that x < y. Show that for all z
∈ (x,y), there exists α ∈ (0,1) so that αx+(1−α)y = z. Now, also
prove that a set X ⊆ R is convex if and only if the set X satisfies
the property that for all x,y ∈ X, with x < y, for all z ∈
(x,y), z ∈ X.
Show that if (x,y,z) is a primitive Pythagorean triple, then X and
Y cannot both be even and cannot both be odd. Hint: for the odd
case, assume that there exists a primitive Pythagorean triple with
X and Y both odd. Then use the proposition "A perfect square always
leaves a remainder r=0 or r=1 when divided by 4." to produce a
contradiction.
PART A: Suppose X and Y are independent. Show that H(X|Y) = H(X)
. (H represents entropy i think)
PART B: Suppose X and Y are independent. Show that H(X,Y) = H(X)
+ H(Y)
PART C: Prove that the mutual information is symmetric, i.e.,
I(X,Y) = I(Y,X) and xi∈X, yi∈Y
Let X, Y be independent exponential random variables with mean
one. Show that X/(X + Y ) is uniformly distributed on [0, 1].
(Please solve it with clear explanations so that I can learn it.
I will give thumbs up.)
Q1
(a) If k(x,y) and l(x,y) are 2
utility functions and are quasiconcave then show m(x,y)=min
(k(x,y,),l(x,y) is also quasiconcave.
(b) Show that k(x,y) is strictly quasiconcave if and
only if the preference relation (>~) is strictly
convex.
f(x,y)=30(1-y)^2*x*e^(-x/y). x>0. 0<y<1.
a). show that f(y) the marginal density function of Y is a Beta
random variable with parameters alfa=3 and Beta=3.
b). show that f(x|y) the conditional density function of X given
Y=y is a Gamma random variable with parameters alfa=2 and
beta=y.
c). set up how would you find P(1<X<3|Y=.5). you do not
have to do any calculations