Question

Bipolar junction transistor

V-V_BE=B*I_B+D*I_C

what does it mean​ B=? and D=?

S_I=dI_C/dI_CBO=(1+h_fe)*B/(B+D*h_fe) IF B,D=0 S_I=? AND B=D S_I=?

S_V=dI_C/dV_BE=(-h_fe)/(B+D*h_fe) IF B,D=0 S_V=? AND B=D S_V=?

S_H=dI_C/dh_fe=I_CQ*B/(h_fe*(B+D*h_fe)) IF B,D=0 S_h=? B=D S_h=?

Answer 1

The Circuit diagram for thee question is shown below :

Here the notations are as follows :

Base Current

Collector Current

Emitter Current

Base Resistance

Emitter Resistance

Collector Resistance.

Volatge Between base and Emitter .

and is almost equal to 1

Solution of question 1 :

Now applying Kirchoff VOltage Law to Input Loop we get

---------------------------------------------------- Equation 1

Now,

since is almost equal to 1,

can be considered equal to

hence ------------------------------------------------------------------- Equation 2

From Equation 1 and 2 we get,

Now by comparing with the given equation,

we get,

and   

Solution of

Solution for :

Solution for :

I hope the answer to the question is clear.