A sample of ozone gas occupies 225 mL at 1.00 atm and 0 °C. If the...

A sample of ozone gas occupies 225 mL at 1.00 atm and 0 °C. If the volume of the gas is 625 mL at 25 °C, what is the pressure?

Expert Solution

Intial final

P1 = 1atm P2 =

V1 = 225ml V2 = 625ml

T1 = 0⁰C = 0+ 273 = 273K T2 = 25⁰C = 25+ 273 = 298K

P1V1/T1 = P2V2/T2

P2 = P1V1T2/T1V2

= 1*225*298/273*625 = 0.393 atm >>>>>answer

queen_honey_blossom answered 2 years ago

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