Consider the equilibrium reaction. H2(g) + I2(g) ⇌ 2 HI(g) In
this case, 1.000 M H2...
Consider the equilibrium reaction. H2(g) + I2(g) ⇌ 2 HI(g) In
this case, 1.000 M H2 reacts with 2.000 M of I2 at a temperature of
441°C. The value of Kc = 67. Determine the equilibrium
concentrations of H2, I2, and HI.
The equilibrium constant Kc for the reaction
H2(g) + I2(g) ⇌ 2 HI(g) is 54.3 at 430 ℃
Calculate the equilibrium concentrations of H2, I2, and HI at 430 ℃
if the initial concentrations are [H2] = [I2] = 0.222 M and [HI] = 0 M.[H2]eq = M[I2]eq = M[HI]eq = M
1. Consider the reaction for
the production of HI from H2 and I2.
H2 (g)+ I2(g) D 2HI(g)
a) What is the initial
concentration of HI?
b) What is the equilibrium
concentration of HI?
c) How is the change in
concentration of HI calculated? Explain:
d) How are the changes in
concentration for H2 and I2 calculated?
Explain
e) How are the equilibrium
concentrations of H2 and I2 calculated?
Explain
Kc for the following reaction is 0.35. H2 (g) + I2 (g) 2 HI (g).
If 1.0 mol of I2 and 1.0 mol of H2 are placed in a 1.0 L vessel,
the equilibrium concentration of HI is :
The answer is 0.46 M, please explain how this value was reached.
Thanks!
The activation energy for the reaction H2(g) + I2(g) ? 2 HI(g)
is 167 kJ/mol, and ?E for the reaction is +28 kJ/mol. What is the
activation energy for the decomposition of HI?
For the following reaction: 2HI (g) ----> H2(g) + I2(g), the
rate law is rate= k[HI]^2. You are starting with 1.0M HI. How long
will the first half-life reaction be? (The professor adds: Note
that since you don't know the value for the rate constant k, just
leave it in your answers.)
Consider the following reaction: H2(g)+I2(g)?2HI(g) The data in
the table show the equilibrium constant for this reaction measured
at several different temperatures. Temperature Kp 150 K 1.4×10?6
175 K 4.6×10?6 200 K 3.6×10?2 225 K 1.1 250 K 15.5 Use the data to
find ?H?rxn and ?S?rxn for the reaction.
For
the reaction
H2(g) + I2(g) ↔ 2HI
the value of the equilibrium constant is 25.
Starting with 1.00mol of each reactant in a 10.L vessel, how
many moles of HI will be present at equilibrium?
At a certain temperature, the equilibrium constant, Kc, for this
reaction is 53.3.
H2(g) + I2 (g) ---> 2 HI (g)
Kc= 53.3
At this temperature, 0.600 mol of H2 and 0.600 mol of I 2 were
placed in a 1.00-L container to react. What concentration of HI is
present at equilibrium?
Consider the following reaction: H2(g) +
I2(g) ⇌ 2HI(g) At a particular temperature, a reaction
mixture at equilibrium contains pressures of H2 = 0.958
atm, I2 = 0.877 atm, and HI = 0.020 atm. At the same
temperature, a second reaction mixture (not at equilibrium)
contains pressures of H2 = 0.621 atm, I2 =
0.621 atm, and HI = 0.101 atm. What will be the partial pressure of
HI when the second reaction mixture reaches equilibrium?
a) 0.0144 atm
b)...
The equilibrium constant Kc is 54.3 at 430°C for the following
reaction: H2(g) + I2(g) ⇌ 2HI(g) Initially, 0.90 M H2, I2, and HI
are introduced into a 5.0-L flask and allowed to come to
equilibrium. What are the equilibrium concentrations of H2, I2, and
HI in the flask? (10 points) (Does the size of flask matter since
Molarity is given?)