The equilibrium constant Kc for the reaction H2(g) + I2(g) ⇌ 2 HI(g) is 54.3 at 430 ℃
The equilibrium constant Kc for the reaction
H2(g) + I2(g) ⇌ 2 HI(g) is 54.3 at 430 ℃
Calculate the equilibrium concentrations of H2, I2, and HI at 430 ℃
if the initial concentrations are [H2] = [I2] = 0.222 M and [HI] = 0 M.
[H2]eq = M
[I2]eq = M
[HI]eq = M
Solutions
Expert Solution
By writing Kc Expression for given reaction and putting the
given Kc and concentration values we can calculate the equilibrium
concentrations of H2 I2 and HI.
The equilibrium constant Kc is 54.3 at 430°C for the following
reaction: H2(g) + I2(g) ⇌ 2HI(g) Initially, 0.90 M H2, I2, and HI
are introduced into a 5.0-L flask and allowed to come to
equilibrium. What are the equilibrium concentrations of H2, I2, and
HI in the flask? (10 points) (Does the size of flask matter since
Molarity is given?)
At a certain temperature, the equilibrium constant, Kc, for this
reaction is 53.3.
H2(g) + I2 (g) ---> 2 HI (g)
Kc= 53.3
At this temperature, 0.600 mol of H2 and 0.600 mol of I 2 were
placed in a 1.00-L container to react. What concentration of HI is
present at equilibrium?
Kc for the following reaction is 0.35. H2 (g) + I2 (g) 2 HI (g).
If 1.0 mol of I2 and 1.0 mol of H2 are placed in a 1.0 L vessel,
the equilibrium concentration of HI is :
The answer is 0.46 M, please explain how this value was reached.
Thanks!
At a certain temperature, the equilibrium constant Kc for this
reaction is 53.3
H2 + I2 ---> 2HI
<---
at this temperature, 0.500 mol of H2 AND 0.500 mol of I2 were
placed in 1.00L container to react. What concentration of HI is
present at equilibrium?
[HI]= ?M
Consider the equilibrium reaction. H2(g) + I2(g) ⇌ 2 HI(g) In
this case, 1.000 M H2 reacts with 2.000 M of I2 at a temperature of
441°C. The value of Kc = 67. Determine the equilibrium
concentrations of H2, I2, and HI.
For
the reaction
H2(g) + I2(g) ↔ 2HI
the value of the equilibrium constant is 25.
Starting with 1.00mol of each reactant in a 10.L vessel, how
many moles of HI will be present at equilibrium?
8. The equilibrium constant Kc for the reaction H2(g)
+ Br2(g) ⇌ 2 HBr(g) is 2.18×106 at 730°C. Starting 3.20
moles of HBr in a 12.0-L reaction vessel, calculate the
concentrations of H2, Br2, and HBr at
equilibrium.
the answer is
[H2] = [Br2] = 1.81×10-4 M
[HBr] = 0.267 M
but how and why?
Consider the following reaction and its equilibrium
constant:
I2(g) + Br2(g) 2 IBr(g) Kc = 1.1 × 102
This reaction mixture contains initially 0.41 M I2 and 0.27 M
Br2. Calculate the equilibrium concentration of I2, Br2, and
IBr?
Please help with this, Can I find a example similar to this
anywhere. I can't figure out some of the parts of this problem.
Find the value of the equilibrium constant Kc at 460°C for the
reaction-
½ H2(g) + ½ I2(g)
HI(g)
given the following data: A 4.50-mol sample of HI is placed in a
1.00-L vessel at 460°C, and the reaction system is allowed to come
to equilibrium. The HI partially decomposes, forming 0.343 mol H2
at equilibrium.
A) 0.0123 B) 0.0081 C) 0.0309 D) 11.1 E) 5.69
For the following reaction: H2(g) +
I2(g)<--->2HI(g) ; Kc=49.5
The beginning concentrations are: H2: 0.10M, I2: 0.050M, and
HI:0
Assume this reaction is not at equilibrium. When it does reach
equilibrium, what will the concentrations be?