In: Chemistry
For the following reaction: 2HI (g) ----> H2(g) + I2(g), the rate law is rate= k[HI]^2. You are starting with 1.0M HI. How long will the first half-life reaction be? (The professor adds: Note that since you don't know the value for the rate constant k, just leave it in your answers.)
Ans. Given,
Initial [HI] = [A]0 = 1.0 M
The order of reaction = 2
At first half of reaction, Final [HI] = ½ x Initial [HI] = ½ x 1.0 M = 0.5 M
Using second order kinetics-
1/ [A] = kt + (1/ [A]0) - equation 1
Where, [A]0 = Initial concentration of X
[A] = Final concentration of X after time t
k = rate constant
t = time of reaction.
Putting the values in above equation-
1/ 0.5 = kt + 1/1 = kt + 1
Or, 2 – 1 = kt
Or, t = 1/k
Therefore, required time to complete first-half reaction (i.e. half of reactant is consumed) = 1/k