In: Mechanical Engineering
Given that,
Oasis Inc. which produces water wants to analyze the mineral contents (gm) in the bottle of 1-liter water they produce.
Especially, they are interested in identifying the magnesium contents, which is one of the most important minerals in the water.
The quality control engineer at their production unit randomly selected 7 bottles and then measured the mineral contents in the samples.
The results obtained from the samples are as shown in the table below:
Sample | Magnesium weight (gm) |
1 | 11.3+0.9=12.2 |
2 | 12.2 |
3 | 11.7+0.9=12.6 |
4 | 12.9 |
5 | 12.5+0.9=13.4 |
6 | 11.7 |
7 | 12.6 |
(a).
Here,
n=7
For the given sample, mean weights are:
=87.6/7
=12.5143
The sample standard deviation is:
S=0.5491
At 92% confidence interval, we will be using a critical value for Z-test because population standard deviation is known (Since it is said in the problem that population standard deviation is similar to sample standard deviation).
So, the critical value is,
Therefore,
The 92% confidence interval is given by:
=(12.151, 12.8776)
(b).
The one-sided confidence interval at the lower tail is:
We have,
=12.5143, S=0.5491 and n=7
So, the one-sided confidence interval at lower tail is,
So, the lower bound is 12.2227.
The lower bound in (a) is less than the lower bound in (b) because the margin of error is reduced in (b). So, this one-sided confidence interval give us a more compact bound.
(c).
The sample for the sample size is:
Hence,
The critical value in (b) =1.4051, S=0.5491
So, the sample size,
=14.8803
=15 (Approximately)
Thus, the company should use a sample size of 15 to get a margin of error of less than 0.20.