Question

The label on a one pint bottle of mineral water lists the following components if the density is the same as pure water and you drink three bottles of water in one day how many milligrams of each component will you obtain? Calcium 28 ppm. Fluoride 0.08ppm. Magnesium 14ppm. Potassium 3.3ppm. Sodium 16ppm

Answer 1

One pint (US) of mineral water= 473.176 ml or 0.473176 Litre

And 1 litre= 2.1133 US pint.

Density of pure water is 0.99823 g/cm³ at 1atm at 20 degree celcius.

1ppm = 1mg/Liter of pure water at STP( Standard temperature and pressure)

For, Calcium 28ppm= 27.94mg/L

Fluoride 0.08ppm= 0.0798 mg/L

Magnesium= 14ppm = 13.9748 mg/L

Potassium =3.3 ppm = 3.294 mg/L

Sodium = 16ppm = 15.971 mg/L

Calculating the amount of each component present

For calcium: simple cross multiplication

27.94 mg - 1000ml

? - 473.176ml

That will give = (27.94 mg× 473.176 ml)/ 1000ml

= 13.220mg for 1 pint

For 3 pint it will be 13.220mg×3= 39.66mg.

Another method is : divide 27.94mg by 2.1133 US pint which will give you 13.220mg/pint and multiply this by 3, that will also give the same answer i.e 39.66 mg for 3 bottles of water.

Similarly for Fluoride 0.08ppm= 0.0798mg/L

0.0798mg/ 2.1133 = 0.0377 mg for 1 pint

0.0377mg× 3 bottles = 0.1132 mg . Hence 0.1132mg of fluoride component is present in 3 bottles of water combined.

For magnesium: 14ppm= 13.9748mg/L

13.9748mg÷ 2.1133 = 6.6127 mg for 1 pint

6.6127×3 bottles= 19.838 mg. Hence 19.838 mg of magnesium is present in 3 bottles combined.

For potassium : 3.3ppm= 3.294mg/L

3.294mg÷ 2.1133 = 1.5586 mg for 1 pint.

1.5586× 3 = 4.6760 mg. Hence 4.6760mg of potassium is present in 3 bottles combined.

For sodium: 16ppm = 15.971 mg/L

15.971 mg÷ 2.1133= 7.5573 mg for 1 pint.

7.5573× 3 = 22.672 mg. Hence 22.672 mg of sodium is present in 3 bottles combined.

Finally Components obtained :

Calcium - 39.66mg

Fluoride - 0.1132mg

Magnesium- 19.838mg

Potassium - 4.6760mg

Sodium- 22.672 mg.