You will be using the equations… q(metal) = -q(water) and q = m x C x...

You will be using the equations… q(metal) = -q(water) and q = m x C x delta T

Two trials have been done. The following procedure is used: The initial temperature of ~200 ml of room temperature water is measured, and ~15 grams of an unknown metal is heated in boiling water from which the initial temperature of the metal is measured. At this point the heated metal is carefully added to the room temperature water, and the temperature of the heated metal in the room temperature water is allowed to equilibrate, and this is measured as the final temperature of both the metal and the water. The specific heat of water, C, is 4.184 J/g C.

The data table (which you must complete…show your work, please) looks as follows:

Trial 1 Trial 2

Mass of water 201.0 g 202.5 g

Mass of metal 16.2 g 15.1 g

Initial T of water 22.2 C 22.4 C

Initial T of metal 94.1 C 93.8 C

Final t of metal & water 27.0 C 26.9 C

Change in T of water

Change in T of metal

Calculated C (specific heat) of metal

Average calculated C of metal: identity of metal:

Expert Solution

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Question

You will be using the equations… q(metal) = -q(water) and q = m x C x...

Solutions

Expert Solution

Related Solutions

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