Question

What is the weight of benzophenone product you would obtain in this lab if you started with 5.6 grams of benzhydrol (and excess [O]) and obtained only an 85% theoretical yield? Show your calculations in gory detail

Answer 1

1 mole of benzophenone yields 1 mole of benzhydrol

moles of benzophenone = 5.6 g/182.217 g/mol

                                       = 0.031 mol

moles of benzhydrol formed = 0.031 mol

theoretical mass of benzhydrol formed = 0.031 mol x 184.24 g/mol

                                                              = 5.66 g

Actual yield is 85% = 0.85 x 5.66 g

                                = 4.81 g