Question
In: Math
For a normal random variable, with μ = 19, and σ = 6, find the following...
| For a normal random variable, with μ = 19, and
σ = 6, find the following probabilities. |
| (a) | Pr(X ≤ 32.2) |
| (b) | Pr(X > 4.00) |
Solutions
milcah answered 2 years agoRelated Solutions
Suppose X is a normal random variable with μ = 600 and σ = 89. Find...
Suppose X is a normal random variable with μ = 600 and σ = 89.
Find the values of the following probabilities. (Round your answers
to four decimal places.)
(a) P(X < 700)
(b) P(X > 350)
(c) P(300 < X < 900)
Suppose X is a normal random variable with μ = 350 and σ = 40. Find...
Suppose X is a normal random variable with μ = 350 and σ = 40.
Find the values of the following probabilities. (Round your answers
to four decimal places.)
(a) P(X < 468)
(b) P(390 < X < 454)
(c) P(X > 390)
A. A normal random variable has an unknown mean μ and a standard deviation σ =...
A. A normal random variable has an unknown mean μ and a standard
deviation σ = 2. If the probability that x exceeds 6.5 is .9732;
find μ.
B. A standard normal random variable has μ = 0 and a standard
deviation σ = 1. Find the probability of less than -2.73.
C. A standard normal random variable has μ = 0 and a standard
deviation σ = 1. Find the probability greater than 3.28.
D. A standard normal random...
? is a normal random variable with µ = 2 and σ = 5. Find the...
? is a normal random variable with µ = 2 and σ = 5. Find the
value of c such that ?{|?−3|>?}=0.7
1. Consider a standard normal random variable with μ = 0 and standard deviation σ =...
1. Consider a standard normal random variable with μ =
0 and standard deviation σ = 1. (Round your answers to
four decimal places.)
(a) P(z
< 2) =
(b) P(z
> 1.16) =
(c) P(−2.31 <
z < 2.31) =
(d) P(z
< 1.82) =
2. Find the following probabilities for the standard normal
random variable z. (Round your answers to four decimal
places.)
(a) P(−1.49 < z < 0.65) =
(b) P(0.56 < z < 1.74) =
(c) P(−1.54 < z < −0.46) =
(d) P(z...
1. Consider a standard normal random variable with μ = 0 and standard deviation σ =...
1. Consider a standard normal random variable with μ =
0 and standard deviation σ = 1. (Round your answers to
four decimal places.)
(a) P(z
< 2) =
(b) P(z
> 1.16) =
(c) P(−2.31 <
z < 2.31) =
(d) P(z
< 1.82) =
2. Find the following probabilities for the standard normal
random variable z. (Round your answers to four decimal
places.)
(a) P(−1.49 < z < 0.65) =
(b) P(0.56 < z < 1.74) =
(c) P(−1.54 < z < −0.46) =
(d) P(z...
Let z denote a random variable having a normal distribution with μ = 0 and σ...
Let z denote a random variable having a normal
distribution with μ = 0 and σ = 1. Determine each of the
probabilities below. (Round all answers to four decimal
places.)
(a) P(z < 0.2) =
(b) P(z < -0.2) =
(c) P(0.40 < z < 0.86) =
(d) P(-0.86 < z < -0.40)
=
(e) P(-0.40 < z < 0.86) =
(f) P(z > -1.24) =
(g) P(z < -1.5 or z > 2.50) =
Let z denote a random variable having a normal distribution with μ = 0 and σ...
Let z denote a random variable having a normal
distribution with μ = 0 and σ = 1. Determine each
of the following probabilities. (Round all answers to four decimal
places.)
(a)
P(z < 0.1) =
(b)
P(z < −0.1) =
(c)
P(0.40 < z < 0.85)
=
(d)
P(−0.85 < z < −0.40)
=
(e)
P(−0.40 < z < 0.85)
=
(f)
P(z > −1.25) =
(g)
P(z < −1.5 or
z > 2.50) =
Let z denote a...
Consider a standard normal random variable with μ = 0 and standard deviation σ = 1....
Consider a standard normal random variable with μ = 0
and standard deviation σ = 1. (Round your answers to four
decimal places.)
(a)
P(z < 2) =
(b)
P(z > 1.13) =
(c)
P(−2.39 < z < 2.39)
=
(d)
P(z < 1.88) =
A normal random variable x has mean μ = 1.8 and standard deviation σ = 0.18....
A normal random variable x has mean μ = 1.8
and standard deviation σ = 0.18. Find the probabilities of
these X-values. (Round your answers to four decimal
places.)
(a)
1.00 < X < 1.50
(b)
X > 1.39
(c)
1.45 < X < 1.60
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