Question

Java. If possible please put explanations for each line of code.

Write a test program that prompts the user to enter a series of integers and displays whether the series contains runLength consecutive same-valued elements. Your program’s main() must prompt the user to enter the input size - i.e., the number of values in the series, the number of consecutive same-valued elements to match, and the sequence of integer values to check. The return value indicates whether at least one run of runLength elements exists in values. Implement the test program as part of the NConsecutive class (the main() method is already in place at the end of the class).

Enter the number of values: 3
How many consecutive, same-valued elements should I look for? 3
Enter 3 numbers: 5 5 5
The list has at least one sequence of 3 consecutive same-valued elements
Enter the number of values: 3
How many consecutive, same-valued elements should I look for? 4
Enter 3 numbers: 5 5 5
The list has no sequences of 4 consecutive same-valued elements

Answer 1

Here is the code:

import java.util.Scanner;

public class Main
{
   public static void main(String[] args) {
   //Scanner Object for input
       Scanner sc = new Scanner(System.in);
      
       //Taking number of values as input
       System.out.print("Enter the number of values: ");
       int n = sc.nextInt();
      
       //Array declaration for storinf values
       int arr[] = new int[n];
      
       //Taking input of How many consecutive elements to find
       System.out.print("How many consecutive, same-valued elements should I look for?: ");
       int c = sc.nextInt();
      
       System.out.print("Enter "+n+" numbers: ");
      
       //Taking the numbers as input and storing them to the array
       for(int i=0; i<n; i++)
       {
       arr[i] = sc.nextInt();
       }
      
       //Condition if the number of consecutive elements to be found are less than or equal to total elements
       if(c<=n)
       {
      
       //Flag variable
       int f=0;
      
       //Checking each consecutive array possible
       for(int i=0; i<=(n-c); i++)
       {
       //If all the elements are not same, turn f=1
       f=0;
       for(int j=i; j<i+c-1; j++)
       {
       if(arr[j] != arr[j+1])
       f=1;
       }
      
       //If f remains zero, that means, we found a pattern
       if(f==0)
       break;
       }
      
       //Output based on flag variable
       if(f==0)
       {
       System.out.println("The list has at least one sequence of "+c+" consecutive same-valued elements");
       }
       else
       {
       System.out.println("The list has no sequences of "+c+" consecutive same-valued elements");
       }
       }
       else
       {
       System.out.println("The list has no sequences of "+c+" consecutive same-valued elements");
       }
   }
}

Output:

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