In: Math
For given list of members in a universal set U.
Members A B
1 a1 b1
2 a2 b1
3 a3 b2
4 a1 b2
5 a1 b2
6 a2 b1
7 a3 b1
8 a1 b2
9 a1 b2
10 a3 b2
Write Probability distribution table for
(a) P(A, B)
(b) P(A)
(c) P(B)
(d) P(A|B=b1)
For given list of members in a universal set U.
Member | A | B |
1 | a1 | b1 |
2 | a2 | b1 |
3 | a3 | b2 |
4 | a1 | b2 |
5 | a1 | b2 |
6 | a2 | b1 |
7 | a3 | b1 |
8 | a1 | b2 |
9 | a1 | b2 |
10 | a3 | b2 |
Write Probability distribution table for
(a) P(A, B)
Number of cases of ( A, B ) = { a1 b1 , a2 b1, a3 b2, a1 b2, a3 b1 } = 5
To calculate probability of each case divide the number of occurances by 10.
Member | a1 b1 | a2 b1 | a3 b2 | a1 b2 | a3 b1 |
Probability | 1/10 | 2/10 | 2/10 | 4/10 | 1/10 |
(b) P(A)
Number of cases of ( A ) = { a1 ,a2, a3 } = 3
To calculate probability of each case divide the number of occurances by 10.
Member | a1 | a2 | a3 |
Probability | 5/10 | 2/10 | 3/10 |
(c) P(B)
Number of cases of ( B ) = { b1 ,b2 } = 2
To calculate probability of each case divide the number of occurances by 10.
Member | b1 | b2 |
Probability | 4/10 | 6/10 |
(d) P(A | B = b1)
Number of cases of (A | B = b1) = { a1 b1, a2 b1, a3 b1 } = 3
To calculate probability of each case divide the number of occurances by 4 since total number of cases of b1 is 4.
Member | a1 | b1 | a2 | b1 | a3 | b1 |
Probability | 1/4 | 2/4 | 1/4 |