Question

In: Chemistry

Calculate the standard enthalpy change for the following reaction at 25 degrees C. HCl(g) + NaOH(s)...

Calculate the standard enthalpy change for the following reaction at 25 degrees C.

HCl(g) + NaOH(s) ---> NaCl(s) + H2O(l)

Solutions

Expert Solution

From standard table,

Hfo of

HCl(g) = -92.3 kJ/mol

NaOH(s) = -425.8 kJ/mol

NaCl(s)= -411.2 kJ/mol

H2O(l) = -285.8 kJ/mol

Now, Hrxno = moles *Hfo (products) - molesHfo (reactants)

Hrxno = (moles*Hfo (NaCl(s)) +(moles *Hfo (H2O(l))) -(moles *Hfo (HCl(g))) -(moles *Hfo (NaOH(s)))

Hrxno = -411.2 kJ/mol -285.8 kJmol + 92.3 kJ/mol + 425.8 kJ/mol = -178.9 kJ/mol


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