In: Chemistry
Calculate the enthalpy change for the reaction:
4 Fe(s) + 3 O2(g) → 2 Fe2O3(s) ΔH°rxn = ?
where:
2 Fe(s) + 6 H2O(ℓ) → 2 Fe(OH)3(s) + 3 H2(g) ΔH1° = +321.8 kJ
2 H2O(ℓ) → 2 H2(g) + O2(g) ΔH2° = +571.7 kJ
Fe2O3(s) + 3 H2O(ℓ) → 2 Fe(OH)3(s) ΔH3° = +288.6 kJ
∆H°rxn of given equation can be calculated by using equations with known ∆H°rxn.
Answer: ∆H°rxn = -1648.7 kJ.