In: Chemistry
Answer the following for the reaction:
NiCl2(aq)+2NaOH(aq)→Ni(OH)2(s)+2NaCl(aq)
How many milliliters of 0.200M NaOHsolution are needed to react with 34.0 mL of a 0.370 M NiCl2 solution?
Express your answer with the appropriate units.
NiCl2(aq)+2NaOH(aq)→Ni(OH)2(s)+2NaCl(aq)
1 mole 2 moles
NaOH NiCl2
M1 = 0.2M M2 = 0.37M
V1 = V2 = 34ml
n1 = 2 n2= 1
M1V1/n1 = M2V2/n2
V1 = M2V2n1/M1n2
= 0.37*34*2/0.2*1 = 125.8ml >>>>>.answer