In: Chemistry
Answer the following for the reaction:
Pb(NO3)2(aq) + 2KCl (aq) ⟶ PbCl2(s) + 2KNO3(aq)
a) How many grams of PbCl2 will be formed from 50.0 mL of a 1.50 M KCl solution?
b) How many mL of a 2.00 M Pb(NO3)2 solution will react with 50.0 mL of a 1.50 M KCl solution?
a) No. of mole = molarity volume of solution in liter
no. mole of KCl = 1.50M 0.050 L = 0.075 mole
According to reaction 2 mole of KCl produce 1 mole of PbCl2 then 0.075 mole of KCl produce 0.075/2 = 0.0375 mole of PbCl2
molar mass of PbCl2 = 278.1 gm/mole that mean 1 mole of PbCl2 = 278.1 gm
then 0.0375 mole of PbCl2 = 278.1 0.0375 = 10.42875 gm
10.42875 gm of PbCl2 will be formed from 50.0 mL of a 1.50 M KCl solution.
b)
No. of mole = molarity volume of solution in liter
no. mole of KCl = 1.50M 0.050 L = 0.075 mole
According to reaction 2 mole of KCl react with 1 mole of Pb(NO3)2 then 0.075 mole of KCl require 0.075/2 = 0.0375 mole of Pb(NO3)2
volume of solution in liter = no. of mole/molarity = 0.0375/2 = 0.01875 L = 18.75 ml
18.75 ml of a 2.00 M Pb(NO3)2 solution will react with 50.0 mL of a 1.50 M KCl solution