Calculate ΔG° for the following reaction as written Ni2+ (aq) + Sn (s) → Ni (s)...

Calculate ΔG° for the following reaction as written

Ni²⁺ (aq) + Sn (s) → Ni (s) + Sn²⁺ (aq)

given the following reduction half-reactions and standard reduction potentials.

Sn²⁺ (aq) + 2 e^- → Sn (s) E° = -0.15V

Ni²⁺ (aq) + 2 e^- → Ni (s) E° = -0.25V

Solutions

Expert Solution

anode reaction: oxidation takes place

Sn(s) -------------------------> Sn+2 (aq) + 2e- , E⁰_Sn+2/Sn = - 0.15 V

cathode reaction : reduction takes palce

Ni+2(aq) + 2e- -----------------------------> Ni(s) , E⁰_Ni+2/Ni = -0.25V

--------------------------------------------------------------------------------

net reaction: Ni²⁺ (aq) + Sn (s) → Ni (s) + Sn²⁺ (aq)

E⁰_cell= E⁰_cathode- E⁰_anode

E⁰_cell= E⁰_Ni+2/Ni - E⁰_Sn+2/Sn

= -0.25 - (-0.15)

= -0.10 V

detla G⁰ = -nF E_cell⁰

= - 2x 96, 485 x (-0.10)

= 19297 J

= 19.3 kJ

ΔG° = 19.3 kJ

queen_honey_blossom answered 11 months ago

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