Answer the following for the reaction: Pb(NO3)2(aq)+2KCl(aq)→PbCl2(s)+2KNO3(aq) How many milliliters of a 2.05 M Pb(NO3)2 solution...

Answer the following for the reaction: Pb(NO3)2(aq)+2KCl(aq)→PbCl2(s)+2KNO3(aq)

How many milliliters of a 2.05 M Pb(NO3)2 solution will react with 40.5 mL of a 1.45 M KCl solution? Please show work!

Thanks

Expert Solution

Pb(NO3)2(aq)+2KCl(aq)→PbCl2(s)+2KNO3(aq)

Pb(NO3)2 KCl

M1 = 2.05 M M2 = 1.45M

V1 = V2 = 40.5ml

n1 = 1 mole n2 = 2

M1V1/n1 = M2V2/n2

V1 = M2V2n1/n2M1

= 1.45*40.5*1/2*2.05 = 14.32 ml

volume of Pb(NO3)2 solution is 14.32 ml

queen_honey_blossom answered 2 years ago

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