Question

In: Chemistry

For the reaction Ca(OH)2(s)+2HCl(aq)→CaCl2(aq)+2H2O(l) a) How many grams of Ca(OH)2 are required to react completely with...

For the reaction Ca(OH)2(s)+2HCl(aq)→CaCl2(aq)+2H2O(l)

a) How many grams of Ca(OH)2 are required to react completely with 430 mL of 0.450 M HCl?

b) How many kilograms of Ca(OH)2 are required to react with 333 L of a HCl solution that is 24.28% HCl by mass, and has a density of 1.12g/mL?

Expert Solution

Ca(OH)2 + 2HCl ------------------------> CaCl2 + 2H2O

a)

moles of HCl = 430 x 0.450 / 1000

= 0.194

1 mole Ca(OH)2 --------------------------------> 2 mole HCl

x mole Ca(OH)2 -----------------------------> 0.194 mole HCl

x = 0.194 x 1 / 2

x = 0.0968

moles of Ca(OH)2 = 0.0968

mass of Ca(OH)2 = 0.0968 x 74.09

= 7.17 g

mass of Ca(OH)2 = 7.17 g

b)

molarity of HCl = mass % x 10 x density / molar mass

= 24.28 x 10 x 1.12 / 36.5

= 7.45 M

volume of HCl = 333 L

moles of HCl = molarity x volume

= 7.45 x 333

= 2481

moles of Ca(OH)2 = 2481 / 2

= 1240.5

mass of Ca(OH)2 = 1240.5 x 74.09

= 91907 g

= 91.9 kg

mass of Ca(OH)2 required = 91.9 kg

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