In: Statistics and Probability
Environmentalists who were worried about the presence of barnacles along the Pacific Coast wanted to see whether Oregon had more barnacles than California. They randomly selected 7 locations in California and 6 locations in Oregon. Working at the edge of the water in each location, they put down frames that covered 0.25 square meters and counted the barnacles inside the frame. Their results are summarized in the table below.
Group |
State |
# of Locations (n) |
Sample Mean Number of Barnacles (x) |
Sample Standard Deviation (s) |
1 |
Oregon |
6 |
26.9 |
1.49 |
2 |
California |
7 |
11.9 |
2.90 |
a. (2 points) What degrees of freedom would you use in the two-sample hypothesis test to compare Oregon and California? Why?
b. What is the test statistic for comparing the mean densities of barnacles in Oregon and California? Show your work.
c. The environmental scientists who conducted this study published a report which concluded that “the average number of barnacles per 0.25 m2 was statistically significantly higher in Oregon than in California, with α = 0.001.” Do your results agree with their published report?
(a)
The degrees of freedom would you use in the two-sample hypothesis test to compare Oregon and California = n1 + n2 - 2 = 6 + 7- 2 = 11 ,
since it an independent samples t test with degrees of frredom for Sample 1 = 6 and degrees of frredom for Sample 2 = 7.
(b)
Pooled Standard Deviation (sP) is given by:
the test statistic for comparing the mean densities of barnacles in Oregon and California is given by:
(c)
= 0.001
df = 11
One Tail - Right Side Test
From Table,critical value of t = 4.025
Since the claculated value of t 11.397 is greater than critical value of t = 4.025, the difference is significant. Reject null hypothesis.
So,
Answer is:
Our results agree with their published report that “the average number of barnacles per 0.25 m2 was statistically significantly higher in Oregon than in California, with α = 0.001".