Show calculations and briefly describe how you will make the following solutions: 50.00 mL of 0.200...

Show calculations and briefly describe how you will make the following solutions:
1. 50.00 mL of 0.200 M Fe(NO3)3(aq) solution from iron(III) nitrate nonahydrate
2. 200.00 mL of a 2.00 mM KSCN(aq) solution from potassium thiocyanate.
3. 100.00 mL of 1.00 M CoCl2(aq) solution from cobalt(II) chloride hexahydrate.
Write the equilibrium expression for parts A, B, and C of the lab based on the equations that are shown in the prior section.
Look at the expression for cobalt complexation with chloride ions (Part B of the lab). How would doubling the amount of water in the reaction vessel affect the product concentrations compared to the reactant concentrations?
How is the [ ] used in metal complexes like the cobalt tetrachloride complex [CoCl4]2- different from the [ ] used in the general equilibrium expression that follows?

K=[B]2[C]/[A

Expert Solution

queen_honey_blossom answered 1 year ago

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