Question

In: Chemistry

Calculate the pH values of the following solutions (you must show the procedure of calculations: a-mole...

Calculate the pH values of the following solutions (you must show the procedure of calculations:

a-mole of formic acid and 0.02 mole of NaOH diluted to 1L. (formic acid pK=3.75).

b-An aspartic acid solution if the alpha carboxyl is 1/2 dissociated. (aspartic acid pK1= 2.0, pK2=9.9, pKside=3.9)

Expert Solution

a)

moles of formic acid = 1

moles of NaOH = 0.02

HCOOH + NaOH -----------------> HCOONa + H2O

1 0.02 0 0

0.98 0 0.02 0.02

here salt and acid remained. so it forms acidic buffer.

pH = pKa + log [salt / acid]

= 3.75 + log [0.02 / 0.98]

= 2.06

pH = 2.06

b)

At 1/2 dissociation pH = pKa1

pH = 2.0

queen_honey_blossom answered 10 months ago

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