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Consider the following 50.00 mL of 0.300 M acetic acid (HC2H3O2) was titrated with 0.200 M...

Consider the following 50.00 mL of 0.300 M acetic acid (HC2H3O2) was titrated with 0.200 M potassium hydroxide (KOH).

HC2H3O2 + KOH H2O + C2H3O2-K+

A. Calculate the pH of the solution when 20.00 mL of 0.200 M KOH is added.

B. Calculate the pH of the solution when 40.00 mL of 0.200 M KOH is added.

C. Calculate the pH of the solution when 50.00 mL of 0.200 M KOH is added.

Solutions

Expert Solution

A. Calculate the pH of the solution when 20.00 mL of 0.200 M KOH is added.

millimoles of CH3COOH = 50 x 0.3 = 15

millimoles of KOH = 20 x 0.2 = 4

CH3COOH + KOH -------------------------> CH3COOK + H2O

15                    4                                               0                 0

11                     0                                              4                4

pH = pKa + log [CH3COOK / CH3COOH ]

pH = 4.74 + log (4 /11)

pH = 4.30

B. Calculate the pH of the solution when 40.00 mL of 0.200 M KOH is added.

millimoles of KOH = 40 x 0.2 = 8

CH3COOH + KOH -------------------------> CH3COOK + H2O

15                    8                                               0                 0

7                    0                                                8            8

pH = pKa + log [CH3COOK / CH3COOH ]

pH = 4.74 + log (8 /7)

pH = 4.80

C. Calculate the pH of the solution when 50.00 mL of 0.200 M KOH is added.

millimoles of KOH = 50 x 0.2 = 10

CH3COOH + KOH -------------------------> CH3COOK + H2O

15                    10                                               0                 0

1                     0                                              10            10

pH = pKa + log [CH3COOK / CH3COOH ]

pH = 4.74 + log (10 /1)

pH = 5.74

queen_honey_blossom answered 2 years ago
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