Show how you will prepare 100 ml of each of the solutions you will use for...

Show how you will prepare 100 ml of each of the solutions you will use for the solubility tests; (i) 6M NaOH, 6M HCl and 10% NaHCO3.

Expert Solution

1) 6M NaOH,
NaOH Molecular weight(M_NaOH )= 40gmol^-1
Mass for the preparation=
100ml=100cm³
m/M_NaOH = 6mol /1000cm³ * 100cm³

m/40gmol^-1 = 6mol /1000cm³ * 100cm³

m= 24g
Accuarately weight 24g of NaoH pallets by the Analytical balance and Added to the 100ml Volumetric flask. Then dissolve it with distilled water. After that it top up to the level of 100ml. Now it is a 6M NaOH solution......

2) 6M HCl,
HCl Molecular weight(M_HCl) = 36.5gmol^-1

Mass for the preparation=

m/M_HCl = 6mol/1000cm³ * 100cm³
m/36.5gmol^-1 = 6mol/1000cm³ * 100cm³

m = 21.9g
Accuarately weight 21.9g of solid format of HCl by the Analytical balance and Added to the 100ml Volumetric flask. Then dissolve it with distilled water. After that it top up to the level of 100ml. Now it is a 6M HCl solution......

3)
10% NaHCO₃
10% NaHCO3 means 10grams present in 100ml solution.
Molecular weight of NaHCO₃ = 84gmol^-1
Mass for the preparation= 10g

Accuarately weight 10g of solid format of NaHCO3 by the Analytical balance and Added to the 100ml Volumetric flask. Then dissolve it with distilled water. After that it top up to the level of 100ml. Now it is a 10% NaHCO3 solution......

queen_honey_blossom answered 2 years ago

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