What volume, in mL, of a 0.2089 M KI solution contains enough KI to react exactly...

What volume, in mL, of a 0.2089 M KI solution contains enough KI to react exactly with the Cu(NO₃)₂ in 43.88 mL of a 0.3842 M solution of Cu(NO₃)₂?

2Cu(
NO3)2+4KI-----2CuI+I2+4KNO3

Expert Solution

calculate mole of Cu(NO₃)₂

no. of mole = Molarity volume of solution in liter

no. of mole of Cu(NO₃)₂ = 0.3842 M 0.04388 L = 0.016858696 mole

According to reaction 2 mole of Cu(NO₃)₂ react with 4 mole of KI then to react with 0.016858696 mole of

Cu(NO₃)₂ require = 0.016858696 4 / 2 = 0.033717392 mole of KI

volume of solution in liter = no. of mole / Molarity

volume of KI = 0.033717392 / 0.2089 = 0.1614 liter = 161.4 ml

161.4 ml 0.2089 M KI solution contains enough KI to react exactly with the Cu(NO₃)₂ in 43.88 mL of a 0.3842 M solution of Cu(NO₃)₂

queen_honey_blossom answered 1 year ago

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