In: Chemistry
If 36.0 mL of H3PO4 react exactly with 80.0 mL of 0.500 M NaOH, what is the concentration of the phosphoric acid?
H3PO4 + 3NaOH --------> Na3PO4 + 3H2O
1 mole 3 moles
H3PO4 NaOH
M1 = M2 = 0.5M
V1 = 36ml V2 = 80ml
n1 = 1 n2 = 3
M1V1/n1 = M2V2/n2
M1 = M2V2n1/V1n2
= 0.5*80*3/36*1 = 3.34M >>>> answer