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If 36.0 mL of H3PO4 react exactly with 80.0 mL of 0.500 M NaOH, what is...

If 36.0 mL of H3PO4 react exactly with 80.0 mL of 0.500 M NaOH, what is the concentration of the phosphoric acid?

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Expert Solution

        H3PO4 + 3NaOH --------> Na3PO4 + 3H2O

      1 mole        3 moles

    H3PO4                                                      NaOH

M1 =                                                           M2 = 0.5M

V1 = 36ml                                                     V2 = 80ml

n1 = 1                                                         n2 = 3

           M1V1/n1     =      M2V2/n2

           M1                 =    M2V2n1/V1n2

                                  = 0.5*80*3/36*1   = 3.34M >>>> answer

                          

queen_honey_blossom answered 1 year ago
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