Question

In: Statistics and Probability

The sample mean salary of 500 NBA players is 7 million dollars. We also know that...

The sample mean salary of 500 NBA players is 7 million dollars. We also know that the population standard deviation is 1 million dollars. We want to construct a confidence interval for population mean with 95% confidence. What will be the length of our confidence interval (in terms of million dollars)?

Solutions

Expert Solution

7   1.96 ( 1 / 500 )

7   0.0877

( 6.9123 , 7.0877 )

At 95 % CI for population Mean is ( 6.9123 , 7.0877 )

----------------------------------------------------------------

Length of the interval is = upper confidence Interval - lower Confidence Interval

Length of the interval is = 7.0877 - 6.9123

Length of the interval is = 0.1754 Million doller


Related Solutions

The mean salary of NBA players in 1996 was $3 million. You are interested to know...
The mean salary of NBA players in 1996 was $3 million. You are interested to know if the mean salary of NBA players increased between 1996 and 2006. A simple random sample of 90 professional basketball player salaries in 2006 was recorded. salaries from 2006 1538400 2000000 8300000 2950000 3140000 6480000 8000000 398762 2120000 8400000 1100000 2750000 398762 5390000 1150000 1890000 6000000 398762 8890000 8100000 771123 398762 5200000 6270000 1270000 2330000 1020000 1140000 6000000 879360 1138500 10970000 880000 2500000 1540000...
Suppose the height of NBA players are approximately normally distributed, with a mean of 198 cm...
Suppose the height of NBA players are approximately normally distributed, with a mean of 198 cm and a standard deviation of 12 cm. (a) What is the probability that a randomly selected NBA player is taller than 213 cm? (b) Determine the height which 95% of NBA players exceed. (c) What is the probability that a team of 15 randomly selected players has an average height between 195 and 200 cm?
The average height of an NBA player is 6.698 feet. A random sample of 30 players’...
The average height of an NBA player is 6.698 feet. A random sample of 30 players’ heights from a major college basketball program found the mean height was 6.75 feet with a standard deviation of 5.5 inches. At α = 0.05, is there sufficient evidence to conclude that the mean height differs from 6.698 feet? State the null and alternate hypothesis State the critical value(s). Enter the appropriate letter. Calculate the test value Make the decision by rejecting or not...
   (7) To investigate if majors is a factor for starting salary, we collected a random sample...
   (7) To investigate if majors is a factor for starting salary, we collected a random sample of recent graduates. Answered the questions based on the given output.                                                            ANOVA                   Starting Salary Sum of Squares df Mean Square F Sig Between Groups 18296543 3 139432181 2.808 .045 Within Groups 52566751035 47962364 Total 52985047578                                                                            Student-Newman-Keuls Major N Subset for alpha = .05 1 2 a 58 55342.73 c 95 56015.95 56015.95 b 24 57631.70 d 23 57991.03 Sig....
Suppose we are interested in analyzing the weights of NFL players. We know that on average,...
Suppose we are interested in analyzing the weights of NFL players. We know that on average, NFL players weigh 247 pounds with a population standard deviation of 47 pounds. Suppose we take a sample of 30 new players and we find that the average weight from that sample is 237 pounds. We are interested in seeing if the weight of NFL players is decreasing. Show work. What is the standard error? What is the margin of error at 90% confidence?...
Suppose we are interested in analyzing the weights of NFL players. We know that on average,...
Suppose we are interested in analyzing the weights of NFL players. We know that on average, NFL players weigh 247 pounds with a population standard deviation of 47 pounds. Suppose we take a sample of 30 new players and we find that the average weight from that sample is 237 pounds. We are interested in seeing if the weight of NFL players is decreasing. What is the standard error? What is the margin of error at 90% confidence? Using my...
A random sample of professional wrestlers was obtained, and the annual salary (in dollars) for each...
A random sample of professional wrestlers was obtained, and the annual salary (in dollars) for each was recorded. The summary statistics were x = 45,500 and n = 17. Assume the distribution of annual salary is normal with o = 8,500. (a) Find a 90% confidence interval for the true mean annual salary for all professional wrestlers (in dollars). (Round your answers to four decimal places.) (______________ , ______________) kg
We wish to predict the salary for baseball players (yy) using the variables RBI (x1x1) and...
We wish to predict the salary for baseball players (yy) using the variables RBI (x1x1) and HR (x2x2), then we use a regression equation of the form ˆy=b0+b1x1+b2x2y^=b0+b1x1+b2x2. HR - Home runs - hits on which the batter successfully touched all four bases, without the contribution of a fielding error. RBI - Run batted in - number of runners who scored due to a batters's action, except when batter grounded into double play or reached on an error Salary is...
We wish to predict the salary for baseball players (y) using the variables RBI (x1) and...
We wish to predict the salary for baseball players (y) using the variables RBI (x1) and HR (x2), then we use a regression equation of the form ˆy=b0+b1x1+b2x2. HR - Home runs - hits on which the batter successfully touched all four bases, without the contribution of a fielding error. RBI - Run batted in - number of runners who scored due to a batters' action, except when batter grounded into double play or reached on an error Salary is...
1. If we know that a bond has a cost of $500 and that it will...
1. If we know that a bond has a cost of $500 and that it will return $800 in 12 years, what is the interest rate, assuming that it is compounded annually? 2. XYZ corporation earnings per share were $2.78, and its growth rate was 9.5% per year for 10 years. At that rate, how long would it take for its earnings per share to double? 3. If you deposit $500 at the end of each year for 10 years...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT