Question

The average height of an NBA player is 6.698 feet. A random sample of 30 players’ heights from a major college basketball program found the mean height was 6.75 feet with a standard deviation of 5.5 inches. At α = 0.05, is there sufficient evidence to conclude that the mean height differs from 6.698 feet?

State the null and alternate hypothesis

State the critical value(s). Enter the appropriate letter.

Calculate the test value

Make the decision by rejecting or not rejecting the null hypothesis. Since the test value falls in the non-rejection region, we do not reject the null hypothesis.

Conclusion 1. Reject the null hypothesis. At the 5% significance level, there is sufficient evidence to conclude that the average height of NBA players is 6.698 feet.

Conclusion 2. Do not reject the null hypothesis. At the 5% significance level, there is sufficient evidence to conclude that the average height of NBA players is 6.698 feet.

Conclusion 3. Do not reject the null hypothesis. At the 5% significance level, there is sufficient evidence to conclude that the average height of NBA players is different from 6.698 feet.

Conclusion 4. Reject the null hypothesis. At the 5% significance level, there is sufficient evidence to conclude that the average height of NBA players is different from 6.698 feet.

Answer 1

This is the two tailed test .

The null and alternative hypothesis is

H₀ : = 6.75

H_a : 6.75

Test statistic = t

= ( - ) / s / n

= (6.75 - 6.698) / 5.5 / 30

= 0.052

Test statistic = 0.052

Critical value = -2.045 , +2.045

Conclusion 3. Do not reject the null hypothesis. At the 5% significance level, there is insufficient evidence to conclude that the average height of NBA players is different from 6.698 feet.